Matematika Sekolah Menengah Atas Kuis +50:
m + 2m = 3
4²ⁿ × 16⁻¹ = 4¹⁸⁺⁶ⁿ
maka nilai n÷(-m) = ....

Kuis +50:
m + 2m = 3
4²ⁿ × 16⁻¹ = 4¹⁸⁺⁶ⁿ
maka nilai n÷(-m) = ....

Jawaban:

n ÷ (-m) = 5

Penjelasan dengan langkah-langkah:

m + 2m = 3

3m = 3

m = 1

[tex] {4}^{2n} \times {16}^{ - 1} = {4}^{18 + 6n} \\ {( {2}^{2} )}^{2n} \times ( {2}^{4}) {}^{ - 1} = ({2}^{2}) {}^{18 + 6n} \\ {2}^{4n} \times {2}^{ - 4} = {2}^{36 + 12 n} \\ {2}^{4n - 4} = {2}^{36 + 12n} \\ 4n - 4 = 36 + 12n \\ -8n = 40 \\ n = -5 [/tex]

nilai dari n ÷ (-m)

= -5 ÷ (-1)

= -5 × -1

= 5

Menentukan nilai m:

[tex] \rm \: m + 2m = 3[/tex]

[tex] \rm \: (2 + 1)m = 3[/tex]

[tex] \rm \: 3m = 3[/tex]

[tex] \rm \: m = \frac{3}{3} [/tex]

[tex] \boxed{ \rm \: m = 1}[/tex]

....

Menentukan nilai n:

[tex] \rm {4}^{2n} \times {16}^{ - 1} = {4}^{18 + 6n} [/tex]

[tex] \rm {4}^{2n} \times { {(4}^{2} )}^{ - 1} = {4}^{18 + 6n} [/tex]

[tex] \rm {4}^{2n} \times {4}^{ - 2} = {4}^{18 + 6n} [/tex]

[tex] \rm {4}^{2n - 2} = {4}^{18 + 6n} [/tex]

[tex] \rm2n - 2 = 18 + 6n[/tex]

[tex] \rm2n - 6n= 18 +2[/tex]

[tex] \rm - 4n= 20[/tex]

[tex] \rm \: n = \frac{20}{ - 4} [/tex]

[tex] \boxed{ \rm \: n = - 5}[/tex]

....

Menentukan nilai n ÷(-m):

n ÷ (-m)

= -5 ÷ (-1)

= 5 ÷ 1

= 5

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